![]() ![]() With those field names corrected, you should iterate the $payloads array using foreach so that you can get the associative key out as well this is important, because only checked values are sent with the form. ![]() If only the first checkbox is checked ->.Using the naming scheme I've suggested earlier, this would be sent: If only the second checkbox is checked ->.Take note of the topay and topay notation that I'm using, as opposed to your form input values that use topay: Here is the HTML code that i send to this php page: echo '' Īssuming you have properly named the input values, e.g.: However, if I only check the second one (6, 103, "mike"), the output still comes out for (5,101,"joe") When the first checkbox is checked, the output works correctly. When both of these checkboxes are checked, the output works correctly. When I do the first echo in the for loop it correctly prints out the values, but the echos within the do not. For example in the form that I pass to php there are multiple check boxes, and it should only pass the ones that are checked. The $_POST is a checkbox array that I pass in where only the items that are checked will come through. This is the code that I have $payloads = $_POST Thus the expression sizeof( *a ) will yield the size of the original array.I have an html form that passes an array into php and then does a for loop to print out values. In this case dereferencing the pointer within the function you will get an object of the array type. You could determine the number of elements in an array if you pass a pointer to the whole array. So you have to pass to the function explicitly also the number of elements in the array. Thus the expression sizeof( array ) / sizeof( int ) in general will always yield either 1 or 2. That size for example can be equal either to 4 or 8 depending on the used system. Then the expression sizeof( array ) will yield the size of the pointer itself that does not depend on whether the pointer points to a single object of the type int or to the first element of an integer array with a known number of elements in the array. In the beginning of each iteration, expr2 is evaluated. The syntax of a for loop is: for (expr1 expr2 expr3) statement The first expression ( expr1) is evaluated (executed) once unconditionally at the beginning of the loop. If you have a pointer like this int *array for loops are the most complex loops in PHP. If the array does not contain a known sentinel value (as for example character arrays that contain strings have as the sentinel value the terminating zero character '\0') then you can not find its end. ![]() In your case, you could consider 0 or -1 to signify the end of the array, but this convention must be used consistently by all callers of your function. The null byte ( \0) is used to tell the end of C strings, which are arrays of char. ![]() It is common to use a null pointer ( NULL) as such a sentinel for arrays of pointers, such as the char *argv argument of the main() function, but note that int argc is also provided to this function. The array could have a sentinel value as the last element of the array. The array could have a known fixed number of elements If this is not practical, there are different ways to infer the number of elements, relying on a convention that must be adhered to by the callers: The best approach for your function to get the number of elements is to provide it as a separate argument. In this case sizeof(array) evaluates to the size of the pointer, so dividing that by the size of an element is meaningless. sizeof(array) / sizeof(*array) only works for an actual array, not for a pointer, which is what a function receives as an argument, even if the array syntax is used in the function prototype. In C, there is no way to tell the number of elements in an array from a pointer to an element. ![]()
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